new protocol

cristianormoraes8 years ago

Hi Anton,

Could you help me?

I'm trying to develope a new protocol for traccar, and I need to write this to the channel:

#1:135790246811221:1:*,00000000,UP,06030e,0a100b#

where 06030e = date (YYMMDD in 6 characters, in hexadecimal)
and 0a100b = tim (HHMMSS in 6 characters,in hexadecimal)

I'm doing the code bellow but is not correct, could you help-me what I'm doing wrong? I'm not so familiar with java.:

if (channel != null) {
            Date date = new Date();
            
             DateFormat df = new SimpleDateFormat("yy"); 

            String date_str = Long.toHexString(Long.valueOf(df.format(date.getYear())))
                    + Long.toHexString(date.getMonth())
                    + Long.toHexString(date.getDay());

            String hour_str = Long.toHexString(date.getHours())
                    + Long.toHexString(date.getMinutes())
                    + Long.toHexString(date.getSeconds());
            
            String content = "#1:" + imei + ":1:*,00000000,UP,06030e,0a100b#";
            ChannelBuffer buf = ChannelBuffers.dynamicBuffer();
            buf.writeBytes(content.getBytes(Charset.defaultCharset()));
            channel.write(buf);
        }

thanks

Anton Tananaev8 years ago

What is the problem? Date formatting? You can use String format:

String.format("%02x%02x%02x", year, month, day)

The methods you are using to get date components are deprecated. I would recommend to use Calendar class.

cristianormoraes8 years ago

The problem is how can I convert this formmated YYMMHH string to 6 hex caracters .... eg. 06030e

cristianormoraes8 years ago

the column information:

YYMMDD: GPS data date. 6 characters, in hexadecimal, e.g.: Nov.8th,2006: Represents the by 060B08.

cristianormoraes8 years ago

Look at my code:

if (channel != null) {
            Calendar cal = Calendar.getInstance();
            Date date = new Date();
            String date_str = String.format("%02x%02x%02x", cal.getTime().getYear(), cal.getTime().getMonth(), cal.getTime().getDay());
            String hour_str = String.format("%02x%02x%02x", cal.getTime().getHours(), cal.getTime().getMinutes(), cal.getTime().getSeconds());
            String content = "#1:" + imei + ":1:*,00000000,UP,"+ date_str.getBytes() +","+ hour_str.getBytes()+"#";
            ChannelBuffer buf = ChannelBuffers.dynamicBuffer();
            buf.writeBytes(content.getBytes(Charset.defaultCharset()));
            channel.write(buf);
        }

The returned string is wrong:

#1:359672050130411:1:*,00000000,UP,[B@7f07ff6a,[B@d4dd3b6#

Anton Tananaev8 years ago

Why are you calling "getBytes()"? Just use the formatted string.

cristianormoraes8 years ago

I did this, look the return:

2016-03-27 11:34:27 DEBUG: [1B781E98: 6000 > 189.40.84.25] HEX: 23313a3335393637323035303133303431313a313a2a2c30303030303030302c55502c3734303230302c30623232316223

#1:359672050130411:1:*,00000000,UP,740200,0b221b#

740200 = 16-03-27

0b221b = 11:34:27

this is correct?

Anton Tananaev8 years ago

That's what you asked for. It's date and time in hex format. Why are you asking if it's correct? I don't even know what protocol you are trying to implement.

cristianormoraes8 years ago

ok, I will finish all data types of the protocol and you send to your email to you add in traccar.

thank you for the help.

Anton Tananaev8 years ago

Thanks. Please send the documentation along with it if possible.